Class 10 Math Unit 6 Exercise 6.1 Solved – Vectors in Plane (PECTAA 2026)

Quadrants, Vector Notation, Magnitude, Unit Vectors & Parallel Vectors | Punjab Boards

Prepared by Muhammad Tayyab, Subject Specialist Mathematics, Govt Christian High School Daska

πŸ“Œ Based on National Curriculum 2023 / PECTAA 2026 Syllabus

πŸ“– What's Inside: This exercise covers quadrants, plotting points, vector notation, magnitude, unit vectors, and parallel vectors. Perfect for Punjab Boards exam preparation.

⬇️ Download PDF (Exercise 6.1 Solved – Unit 6 Exercise 6.1 Solution PDF)

πŸ“š Related Resources – Unit 6: Vectors in Plane

Class 10 Math Unit 6 Exercise 6.1 – Vectors in Plane: Complete Guide

Unit 6 of Class 10 Mathematics introduces students to vectors in the plane, one of the most visual and application-rich topics in the PECTAA 2026 syllabus. Exercise 6.1 is the entry point into this chapter, and it lays the groundwork that every later exercise in Unit 6 β€” including Exercise 6.2, Exercise 6.3, and the Unit 6 Review Exercise β€” builds on. This page walks through every question of Exercise 6.1 step by step, prepared according to the unified Punjab textbook used across all 10 BISE Punjab boards.

What You Will Learn

By working through Exercise 6.1, students learn how to identify the four quadrants of the Cartesian plane, plot points and vectors accurately, write a vector in the standard form \(x\hat{i} + y\hat{j}\), calculate the magnitude of a vector using the distance-style formula, convert any vector into a unit vector, and test two vectors for parallelism using the scalar multiple condition. These are not isolated skills β€” they are the building blocks used throughout the rest of Unit 6 and reappear in Unit 7 (Trigonometry) when vectors are combined with angles and direction.

Topics Covered in This Exercise

Why Exercise 6.1 Is Important

Exercise 6.1 is the foundation exercise of Unit 6. Punjab Board exam papers frequently draw at least one short question directly from this exercise, particularly on magnitude, unit vectors, and parallel vectors, because these three concepts are easy to test in a single line and easy for examiners to vary slightly from year to year. Students who skip Exercise 6.1 and jump straight into Exercise 6.2 or Exercise 6.3 often struggle, because those exercises assume fluency with the notation and formulas introduced here.

Punjab Board Preparation

For students preparing for board exams under any of the 10 BISE Punjab boards, this exercise should be treated as compulsory practice rather than optional revision. The magnitude formula, the unit vector formula, and the parallel vector condition \((\bar{b} = \lambda \bar{a})\) are the three most commonly repeated question types from Unit 6 in past board papers. Practising every part of Q5, Q6, and Q9 by hand β€” not just reading the worked solution β€” is the single most effective way to prepare for this portion of the paper.

PECTAA 2026 Syllabus Alignment

These solved notes are aligned with the Punjab Education & Curriculum Textbook Authority (PECTAA) 2026 syllabus, which follows the National Curriculum 2023 framework for Class 10 Mathematics. The question numbering, formulas, and terminology used on this page match the current Punjab textbook exactly, so students can use it alongside their school textbook without any mismatch in question order or notation.

Exam Tips for Vectors in Plane

Common Mistakes Students Make

Use the table of contents below to jump directly to any question, or scroll through the full solved exercise in order.

Muhammad Tayyab Subject Specialist Mathematics

MSc Mathematics Β· Govt Christian High School Daska, Sialkot, Punjab

Content reviewed against the PECTAA 2026 / National Curriculum 2023 syllabus for Class 10 Mathematics, applicable to all 10 BISE Punjab boards.

Last updated: Source: Punjab Curriculum & Textbook Board (PCTB)
1 Name the Quadrant

(i) (4, 3)

The point (4, 3) lies in Quadrant I.


(ii) (5, βˆ’4)

The point (5, βˆ’4) lies in Quadrant IV.


(iii) (βˆ’6, 2)

The point (βˆ’6, 2) lies in Quadrant II.


(iv) (βˆ’4, βˆ’4)

The point (βˆ’4, βˆ’4) lies in Quadrant III.

2 Plot the Following Points on the Coordinate Plane
Graph showing point (3, -3)

(i) (3, βˆ’3)

Graph showing point (-3, 3)

(ii) (βˆ’3, 3)

Graph showing point (5, 7)

(iii) (5, 7)

Graph showing point (-2, -4)

(iv) (βˆ’2, βˆ’4)

3 Name the Tail and Tip of the Following Vectors
All 6 vector diagrams showing tails and tips: (i) Tail B, Tip A; (ii) Tail P, Tip Q; (iii) Tail S, Tip R; (iv) Tail M, Tip N; (v) Tail A, Tip B; (vi) Tail D, Tip C
(i) Tail: B, Tip: A
(ii) Tail: P, Tip: Q
(iii) Tail: S, Tip: R
(iv) Tail: M, Tip: N
(v) Tail: A, Tip: B
(vi) Tail: D, Tip: C
4 Write Vector \( \overrightarrow{AB} \) in \( x\hat{i} + y\hat{j} \)

(i) \(A(1, -7), B(-2, 4)\)

\[ \begin{aligned} \overrightarrow{AB} &= \overrightarrow{OB} - \overrightarrow{OA} \\ &= (-2\hat{i} + 4\hat{j}) - (\hat{i} - 7\hat{j}) \\ &= -2\hat{i} + 4\hat{j} - \hat{i} + 7\hat{j} \\ &= -3\hat{i} + 11\hat{j} \end{aligned} \]

(ii) \(A(8, 9), B(12, 3)\)

\[ \begin{aligned} \overrightarrow{AB} &= \overrightarrow{OB} - \overrightarrow{OA} \\ &= (12\hat{i} + 3\hat{j}) - (8\hat{i} + 9\hat{j}) \\ &= 12\hat{i} + 3\hat{j} - 8\hat{i} - 9\hat{j} \\ &= 4\hat{i} - 6\hat{j} \end{aligned} \]
5 Find the Magnitude of the Vector

(i) \(\bar{a} = -3\hat{i} + 2\hat{j}\)

\[ |\bar{a}| = \sqrt{(-3)^2 + (2)^2} = \sqrt{9 + 4} = \sqrt{13} \]

(ii) \(\bar{a} = 4\hat{i} - 3\hat{j}\)

\[ |\bar{a}| = \sqrt{4^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5 \]

(iii) \(\bar{a} = \frac{1}{2}\hat{i} + \frac{3}{2}\hat{j}\)

\[ |\bar{a}| = \sqrt{\left(\frac{1}{2}\right)^2 + \left(\frac{3}{2}\right)^2} = \sqrt{\frac{1}{4} + \frac{9}{4}} = \sqrt{\frac{10}{4}} = \frac{\sqrt{10}}{2} \]
6 Find a Unit Vector in the Direction of the Given Vector

(i) \(\bar{a} = -4\hat{i} + 5\hat{j}\)

\[ |\bar{a}| = \sqrt{(-4)^2 + (5)^2} = \sqrt{16 + 25} = \sqrt{41} \] \[ \hat{a} = \frac{\bar{a}}{|\bar{a}|} = -\frac{4}{\sqrt{41}}\hat{i} + \frac{5}{\sqrt{41}}\hat{j} \]

(ii) \(\bar{a} = 6\hat{i} + 8\hat{j}\)

\[ |\bar{a}| = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \] \[ \hat{a} = \frac{6}{10}\hat{i} + \frac{8}{10}\hat{j} = \frac{3}{5}\hat{i} + \frac{4}{5}\hat{j} \]

(iii) \(\bar{a} = \frac{1}{\sqrt{6}}\hat{i} + \frac{1}{\sqrt{6}}\hat{j}\)

\[ |\bar{a}| = \sqrt{\left(\frac{1}{\sqrt{6}}\right)^2 + \left(\frac{1}{\sqrt{6}}\right)^2} = \sqrt{\frac{1}{6} + \frac{1}{6}} = \sqrt{\frac{2}{6}} = \frac{1}{\sqrt{3}} \] \[ \hat{a} = \frac{\bar{a}}{|\bar{a}|} = \frac{\frac{1}{\sqrt{6}}\hat{i} + \frac{1}{\sqrt{6}}\hat{j}}{\frac{1}{\sqrt{3}}} = \frac{1}{\sqrt{2}}\hat{i} + \frac{1}{\sqrt{2}}\hat{j} \]

(iv) \(\bar{a} = \frac{1}{2}\hat{i} + \frac{3}{4}\hat{j}\)

\[ |\bar{a}| = \sqrt{\left(\frac{1}{2}\right)^2 + \left(\frac{3}{4}\right)^2} = \sqrt{\frac{1}{4} + \frac{9}{16}} = \sqrt{\frac{4+9}{16}} = \frac{\sqrt{13}}{4} \] \[ \hat{a} = \frac{\bar{a}}{|\bar{a}|} = \frac{\frac{1}{2}\hat{i} + \frac{3}{4}\hat{j}}{\frac{\sqrt{13}}{4}} = \frac{2}{\sqrt{13}}\hat{i} + \frac{3}{\sqrt{13}}\hat{j} \]
7 Unit Vector Parallel to \( \bar{a} + \bar{b} - 3\bar{c} \)

Given: \(\bar{a} = 5\hat{i} - 7\hat{j}, \bar{b} = -\hat{i} - \hat{j}, \bar{c} = 2\hat{i} + 3\hat{j}\)

Let \(\bar{v} = \bar{a} + \bar{b} - 3\bar{c}\)

\[ \begin{aligned} \bar{v} &= (5\hat{i} - 7\hat{j}) + (-\hat{i} - \hat{j}) - 3(2\hat{i} + 3\hat{j}) \\ &= 5\hat{i} - 7\hat{j} - \hat{i} - \hat{j} - 6\hat{i} - 9\hat{j} \\ &= -2\hat{i} - 17\hat{j} \end{aligned} \]
\[ |\bar{v}| = \sqrt{(-2)^2 + (-17)^2} = \sqrt{4 + 289} = \sqrt{293} \] \[ \hat{v} = \frac{\bar{v}}{|\bar{v}|} = -\frac{2}{\sqrt{293}}\hat{i} - \frac{17}{\sqrt{293}}\hat{j} \]
8 Unit Vector Parallel to \( 3\bar{a} + 2\bar{c} + 4\bar{b} \)

Given: \(\bar{a} = 3\hat{i} - \hat{j}, \bar{b} = -2\hat{i} + 4\hat{j}, \bar{c} = \hat{i} + 2\hat{j}\)

Let \(\bar{v} = 3\bar{a} - 2\bar{c} + 4\bar{b}\)

\[ \begin{aligned} \bar{v} &= 3(3\hat{i} - \hat{j}) - 2(\hat{i} + 2\hat{j}) + 4(-2\hat{i} + 4\hat{j}) \\ &= 9\hat{i} - 3\hat{j} - 2\hat{i} - 4\hat{j} - 8\hat{i} + 16\hat{j} \\ &= -\hat{i} + 9\hat{j} \end{aligned} \]
\[ |\bar{v}| = \sqrt{(-1)^2 + 9^2} = \sqrt{1 + 81} = \sqrt{82} \] \[ \hat{v} = \frac{\bar{v}}{|\bar{v}|} = -\frac{1}{\sqrt{82}}\hat{i} + \frac{9}{\sqrt{82}}\hat{j} \]
9 Which of the Following Vectors are Parallel?

(i) \(\bar{a} = 6\hat{i} + \hat{j}, \bar{b} = 12\hat{i} + 2\hat{j}\)

\[ \bar{b} = 2(6\hat{i} + \hat{j}) = 2\bar{a} \]

Hence, \(\bar{a}\) and \(\bar{b}\) are parallel with \(\lambda = 2\).


(ii) \(\bar{a} = -2\hat{i} + 3\hat{j}, \bar{b} = 6\hat{i} - 9\hat{j}\)

\[ \bar{b} = -3(-2\hat{i} + 3\hat{j}) = -3\bar{a} \]

Hence, \(\bar{a}\) and \(\bar{b}\) are parallel with \(\lambda = -3\).


(iii) \(\bar{a} = 5\hat{i} - 4\hat{j}, \bar{b} = 6\hat{i} - 3\hat{j}\)

\(\bar{a} \neq \lambda \bar{b}\) and \(\bar{b} \neq \lambda \bar{a}\).

Hence, \(\bar{a}\) and \(\bar{b}\) are not parallel.


(iv) \(\bar{a} = 3\hat{i} - 7\hat{j}, \bar{b} = 6\hat{i} - 14\hat{j}\)

\[ \bar{b} = 2(3\hat{i} - 7\hat{j}) = 2\bar{a} \]

Hence, \(\bar{a}\) and \(\bar{b}\) are parallel with \(\lambda = 2\).

10 Vector Thrice in Length but Opposite in Direction

Given vector: \(\bar{v} = 3\hat{i} - 2\hat{j}\)

Three times in length: \(3\bar{v} = 9\hat{i} - 6\hat{j}\)

Opposite in direction: \(-3\bar{v} = -9\hat{i} + 6\hat{j}\)

11 Two Vectors Double in Magnitude (Same & Opposite Direction)

Given vector: \(\bar{v} = 3\hat{i} - 5\hat{j}\)

Double in magnitude in same direction:

\[ 2\bar{v} = 6\hat{i} - 10\hat{j} \]

Double in magnitude in opposite direction:

\[ -2\bar{v} = -6\hat{i} + 10\hat{j} \]

πŸ“ˆ Key Formulas & Quick Revision

🎯 Important Definitions

πŸ“ Important MCQs for Practice

1. The point (βˆ’5, 6) lies in which quadrant?

(a) I   (b) II   (c) III   (d) IV β€” Answer: (b) II

2. If \(\bar{a} = 3\hat{i} + 4\hat{j}\), then \(|\bar{a}|\) equals:

(a) 5   (b) 7   (c) 12   (d) 25 β€” Answer: (a) 5

3. A unit vector always has magnitude equal to:

(a) 0   (b) 1   (c) 2   (d) depends on direction β€” Answer: (b) 1

4. Two vectors \(\bar{a}\) and \(\bar{b}\) are parallel if:

(a) \(|\bar{a}| = |\bar{b}|\)   (b) \(\bar{b} = \lambda \bar{a}\)   (c) \(\bar{a} + \bar{b} = 0\)   (d) none of these β€” Answer: (b) \(\bar{b} = \lambda \bar{a}\)

5. \(\overrightarrow{AB}\) is calculated as:

(a) \(\overrightarrow{OA} - \overrightarrow{OB}\)   (b) \(\overrightarrow{OB} - \overrightarrow{OA}\)   (c) \(\overrightarrow{OA} + \overrightarrow{OB}\)   (d) none β€” Answer: (b) \(\overrightarrow{OB} - \overrightarrow{OA}\)

πŸ† Board Exam Tips & Strategy

❓ Frequently Asked Questions

What is taught in Exercise 6.1 of Class 10 Math Unit 6?

Exercise 6.1 introduces vectors in the plane. It covers identifying quadrants, plotting points, writing vectors in the form \(x\hat{i} + y\hat{j}\), finding the magnitude of a vector, finding a unit vector, and checking whether two vectors are parallel.

How many questions are there in Unit 6 Exercise 6.1?

Exercise 6.1 has 11 questions, ranging from naming quadrants and plotting points to finding magnitudes, unit vectors, and identifying parallel vectors.

Is this solution according to the PECTAA 2026 syllabus?

Yes, these solutions are prepared according to the PECTAA 2026 / National Curriculum 2023 syllabus for Class 10 Mathematics.

Is this Exercise 6.1 solution valid for all Punjab Boards?

Yes, the content follows the unified Punjab textbook and is applicable to students of all 10 BISE Punjab boards.

What is a vector in mathematics?

A vector is a quantity that has both magnitude and direction, usually represented as an arrow from a tail point to a tip point, or in component form as \(x\hat{i} + y\hat{j}\).

How do you find the magnitude of a vector?

The magnitude of a vector \(\bar{a} = x\hat{i} + y\hat{j}\) is found using the formula \(|\bar{a}| = \sqrt{x^2 + y^2}\).

What is a unit vector?

A unit vector is a vector with magnitude equal to 1. It is found by dividing a vector by its own magnitude: \(\hat{a} = \bar{a} / |\bar{a}|\).

Are solved PDF notes available for Exercise 6.1?

Yes, a complete solved PDF for Exercise 6.1 is embedded on this page and available to download for free.

Can I download the Unit 6 Exercise 6.1 solution as a PDF?

Yes, use the Download PDF button on this page to save the complete solved Exercise 6.1 notes to your device.

Is Exercise 6.1 important for Class 10 board exams?

Yes, vectors are a regularly tested topic in Punjab Board papers, and Exercise 6.1 builds the foundational skills of magnitude, unit vectors, and parallel vectors needed for later exercises in Unit 6.

How should students prepare for the Vectors chapter?

Students should practise plotting points and vectors by hand, memorise the magnitude and unit vector formulas, solve each exercise question without looking at the solution first, and then check their working against these solved notes.

Who prepared these Class 10 Math Unit 6 notes?

These notes were prepared by Muhammad Tayyab, Subject Specialist Mathematics at Govt Christian High School Daska, for Hira Science Academy.

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